(7x^5-4x)-(2x^3+4x-8)=0

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Solution for (7x^5-4x)-(2x^3+4x-8)=0 equation:


Simplifying
(7x5 + -4x) + -1(2x3 + 4x + -8) = 0

Reorder the terms:
(-4x + 7x5) + -1(2x3 + 4x + -8) = 0

Remove parenthesis around (-4x + 7x5)
-4x + 7x5 + -1(2x3 + 4x + -8) = 0

Reorder the terms:
-4x + 7x5 + -1(-8 + 4x + 2x3) = 0
-4x + 7x5 + (-8 * -1 + 4x * -1 + 2x3 * -1) = 0
-4x + 7x5 + (8 + -4x + -2x3) = 0

Reorder the terms:
8 + -4x + -4x + -2x3 + 7x5 = 0

Combine like terms: -4x + -4x = -8x
8 + -8x + -2x3 + 7x5 = 0

Solving
8 + -8x + -2x3 + 7x5 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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